So the sum of three consecutive positive integers is three times that of the middle one.

Let the middle number be n, then the first one is n- 1 and the third one is n+ 1.

So (n-1)+n+(n+1) = n-1+n+1= 3n.

Let the middle number be n, then the first two are n- 1 and n-2, and the last two are n+ 1 and n+2.

Therefore, (n-2)+(n-1)+n+(n+1)+(n+2) = = n-2+n-1+n = 5n.

So the sum of five consecutive positive integers is five times the median.