If you can't use division and unknowns, you can only use enumeration:

4+24=28 * * * There are 28 sweets;

4*3= 12 dessert, Qiqi is 3 times higher than An 'an;

Here 1 candy:

(4+ 1)*3= 15 is still smaller than Qiqi's (24- 1)=23 sugar;

Give two sweets:

(4+2)*3= 18 is still smaller than Qiqi's (24-2)=22 sweets;

Give three sweets:

(4+3)*3=2 1 At this time, (24-3)=2 1 sugar;

So Qiqi should give Ann three sweets.

This kind of problem is just a logic for primary school students to exercise, a mixed algorithm of addition, subtraction, multiplication and division. I hope it helps you.