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Solution: When they first met, A and B walked the distance between A and B..

The difference between the travel distances of Party A and Party B is 2× 2 = 4 km.

The second time we met, we walked three distances a and B.

That is, the distance difference between a and b is 4× 3 = 12 km.

When they met for the second time, both A and B had already passed the distance between A and B..

So we take the lengths of a and b at the same time. Their distance difference is constant.

After subtracting the length of a and b; B's journey is 4 kilometers.

After subtracting the length of a and b; Obviously, the distance traveled by A can be calculated as:12+4 =16 ~ km.

After subtracting the length of a and b; The distance taken by b is the same as the distance after subtracting the length of a and b; The sum of the distances traveled by A is the distance between A and B.

12+4+4 = 20km.

Formula: 2× 2 = 4 km.

4× 3 =12km

12+4 = 16 (km)

12+4+4 = 20km.

A: A and B are 20 kilometers apart.

Answer over!