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C position in mathematics
Let the three sides of △a, B and C be A, B and C respectively.

Answer? +b? =c?

a+b+c=30

Answer? +(30-a-c)? =c?

Answer? +900+a? +c? +2ac-60c-60a=c?

arrange

60(a+c)-2a? -2ac=900

60(a+c)-2a(a+c)=900

(60-2a)(a+c)=900

(30-a)(a+c)=450

(30-a)(30-b)=450

Integers with bits A, B and C and (30-a) and (30-b) can be divisible by 450.

30-a & lt; 30,30-b & lt; 30

450=5x5x3x3x2

So 30-a=25, 30-b= 18.

a=5

b= 12

c= 13