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A set of junior one math problems: fast people walk 100 steps, slow people walk 60 steps. If the slow person takes 100 steps first, how many steps does the fast person have to take to catch up?
Let the speed of fast men and slow men be A and B respectively, and the travel time is equal.

Then 100/a=60/b and a/b= 100/60 are obtained.

Suppose the fast runner takes X steps and catches up with the slow runner, which proves that they walk the same distance. At this point, the jogger actually took X steps, so the jogger's journey after the fast runner left is x- 100, and the journey time after the fast runner left is equal.

Then x/a=(x- 100)/b, x=250.

So the fast runner has to walk 250 steps to catch up with the slow runner.