In the rolling process, the horizontal displacement of the center of the circle is 1/4 perimeter plus radius, that is, π+2, and then it moves horizontally by 50, so in the total process, the horizontal displacement of the center of the circle is π+2+50=π+52, and the vertical displacement of the center of the circle is 2, so the moving distance of Pythagorean theorem is [(π+52) 2+.

If the distance in this question refers to the horizontal distance, it is π+52. The final answer is if it refers to the total distance.