Solution: (2) When point P is on line segment AB, the parallel lines passing through point P as AC intersect BC and point F,

∠B=60，→PF=PB=FB=x，

PF CQ，PF=CQ。

△PFE?△CQE

→CE=EF=y .

x+2y=6

y =(- 1/2)* x+3(0 & lt； = x & lt=6)

(3) When point P is on the extension line of line segment BA, the parallel line passing through point P as AC intersects BC and point G,

Similarly △ PGE △ ECQ → EG = CE = Y,

x-2y=6

y =( 1/2)* x-3(x & gt； 6)

Over! NBUZW