1/(1-1/2-1/3) = 6 Answer D.

The idea is to look at how much they do in a day and take this as an equivalent relationship.

1/2 for A and 1/3 for B.

And the three of them do the general task11a day.

So 1/6 of C's total task in a day, and then 1 is divided by him, which is the number of days.

2

This should consider the leap year in a normal year, with 365 days in a normal year and 366 days in a leap year.

2004 is a leap year and 2005 is a flat year, so from July 2003 1 to July 2005 1, there is 365+366=73 1 day, that is, there is 73 1 divided by 7 =/kloc-0. ..

The quickest way to calculate this kind of problem is to divide the number of days by 7, and then add the remainder to the first number of weeks.