Is there an original formula =t/√( 1+t)?

Derive [√( 1+t)? -(3/2)t √( 1+t)]/( 1+t)？

There is (3/2) t = (1+t) at the inflection point, and t = 2.

At this time, the original formula =2/√( 1+2)? =2√3/9

That is 1/x at the extreme value? = 2, x = √ 2/2, and the extreme value is 2√3/9.