So four of these eight numbers are ten digits and four are single digits.
The sum of these eight numbers is 2+3+...+8+9 = 44.
Let the sum of digits of ten digits be x and x be an integer, then the sum of digits of one digit is (44-x).
So x *10+(44-x) =1609x =116.
x = 1 16/9 = 12.88
Contradicting that x is an integer.
So there is no solution.
I hope this helps.
¢Ù Math in the second class of grade five.
The places where the students in Class One, Grade Five pass are represented in pairs: (1, 3), (2, 2), (3, 4), (4, 1