XT =18 (x+1) * (t-3) =18 from the above data sequence equation.
Solve the above formula X=2.
2. Let the number of people on the first day be x, then the number of people on the second day is (x+50).
Since everyone is equal in two days, 4800/x=6000/(x+50) gets x=200.
24 per capita.
3. Let the total number of projects be S, and it takes X days for Team B to complete it alone, then the speed of Team B is (S/x) and the speed of Team A is (S/40), which can be obtained according to the data column equation.
S = (s/x) *10+(s/x+s/40) * 20 gives x=60.
It takes T days for Party A and Party B to complete * *, and the speed of Party B from the above questions is (S/60).
Then solve the countable equation (S/40+S/60)*t=S to get t=24.
4. Suppose B takes t days to complete, then A is (2/3*t) and the total project amount is S,
Then the speed of A is S/(2/3*t) and the speed of B is S/t, and the above data sequence equation can be obtained.
S/(2/3 * t) *10+(s/(2/3 * t)+s/t) * 30 = s gives t+90, so a is 60.
If it takes T days for Party A and Party B to complete the same task, then the solution of the equation (S/90+S/60)*T=S will get T=36.
If the project cost is (0.84+0.56) * 36 = 504,000 to complete the project, and the budget is not enough, it needs to be increased by 4,000 yuan.