1. If A's speed is V A =x, then B is (x+ 1), and if A's time is T A =t, then B is (t-3).

XT =18 (x+1) * (t-3) =18 from the above data sequence equation.

Solve the above formula X=2.

2. Let the number of people on the first day be x, then the number of people on the second day is (x+50).

Since everyone is equal in two days, 4800/x=6000/(x+50) gets x=200.

24 per capita.

3. Let the total number of projects be S, and it takes X days for Team B to complete it alone, then the speed of Team B is (S/x) and the speed of Team A is (S/40), which can be obtained according to the data column equation.

S = (s/x) *10+(s/x+s/40) * 20 gives x=60.

It takes T days for Party A and Party B to complete * *, and the speed of Party B from the above questions is (S/60).

Then solve the countable equation (S/40+S/60)*t=S to get t=24.

4. Suppose B takes t days to complete, then A is (2/3*t) and the total project amount is S,

Then the speed of A is S/(2/3*t) and the speed of B is S/t, and the above data sequence equation can be obtained.

S/(2/3 * t) *10+(s/(2/3 * t)+s/t) * 30 = s gives t+90, so a is 60.

If it takes T days for Party A and Party B to complete the same task, then the solution of the equation (S/90+S/60)*T=S will get T=36.

If the project cost is (0.84+0.56) * 36 = 504,000 to complete the project, and the budget is not enough, it needs to be increased by 4,000 yuan.