Analysis: According to ①, ②, ③ and ④, the sum of the areas of four parallelograms is 14cm2, and the area of quadrilateral ABCD is 1 1cm2. We can find out the area of ⑤, thus finding out the area of rhombus, finding out the side length according to the properties of rhombus, and then finding out the sum of the perimeters of ①, ②, ③ and ④.

Solution: From the meaning of the question: ⑤ area = quadrilateral ABCD area ﹣ (①+②+③+④)=4cm2.

∴∴ The area of ∴∴efgh = 14+4= 18cm2,

∫∠f = 30，

∴: The side length of a diamond is 6 cm.

The sum of the perimeters of the four parallelograms is 2 (AE+Ah+HD+DG+GC+CF+FB+BE) = 2 (EF+FG+GH+He) = 48 cm.

So choose a.