Ab cd intersects at point o, ∴ AO=CO=BO=DO.
∫AE bisects ∠ ∠BAD intersects BC at point E∴∠ BAE =∠ EAD = 45.
* EAC = 15 ∴∠ba0=60
AO = BO
∴∠ABO=60
∵∠Bao+∠ABO+∠AOB = 180 ∴∠aob=60
△ AOB is an equilateral triangle.
That is AB=OA=BO.
∠∠ABC = 90∠EAB = 45。
∠ABC+∠ea b+∠bea = 180 ∴∠bea=45
∴△ABE is an isosceles right triangle.
∴ BE=BA
∵ BE=BA and BA=BO ∴BE=BO.
That is, △OBE is isosceles △
∠∠ABC = 90∠ABO = 60
∴∠OBE=30
∴∠BOE=∠BEO=( 180-30)÷2=75