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Mathematics and geometry problems in the second day of junior high school
Solution: Because angle ABP+ angle ABC= 180 degrees.

Angle ABP= 150 degrees

So the angle ABC=30 degrees.

Because AB parallel CD

So angle ABC= angle C.

So the angle C=30 degrees.

Because angle ADE= angle BPD+ angle c

Because EF is parallel to DP

So angle ade+angle PED+ angle PEF= 180 degrees

Because angle PEG= angle PED+ angle DEG=66 degrees

Because EG bisects the angle CEH

So angle DEG= 1/2 angle DEH.

So angle PED+ angle DEH= 132 degrees.

Because Angel ·PEF = Angel ·PEH

Angle PEH= angle PED+ angle DEH

So: 3=+ angle BPD+2 angle PED+ angle DEH= 180 degrees.

So BPD angle = 18 degrees.