Basic Mathematics of Grade Six —— Engineering Problems

1.b did 15+2 hours, and A finished the work in 2 hours. Let the total workload be 1. The working efficiency of B is (1-112× 2) ÷ (2+15) = 5/102. B A person's working time is 1 ÷ 5/ 12. The working efficiency of x =1100a is1100× 3 = 3/100b is1100× 2 =/kloc. Party B alone is 1÷ 1/50=50 (days). 3. The work efficiency of Party A and Party B is 1/ kloc-0/2, that of Party C is110, and that of Party A, Party B and Party D is1/. The working efficiency of Party A is112+115, and the working time is1÷ (112+).

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A math problem in grade six. For the topic, please see the supplementary question. Please write down the process and ideas of solving the problem.