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Three views on solid geometry in senior high school mathematics
The geometric figure to be solved is an inverted regular hexagonal cone.

The middle line segment of the front view is equal to the sum of the left and right line segments, which is half the side length of the regular triangle, and is 1, which is also the side length of the geometric top view.

The height of the triangle in the front view can be calculated as √(2? - 1? )=√3.

The height of the side view triangle is equal to the height of the front view triangle, that is, √3.

The distance between two parallel sides in the top view is 2√( 1? -( 1/2)? )=√3.

The base of the triangle in the test drawing is equal to the distance between the upper and lower parallel sides in the top view, which is √3.

So the area of the side view is √3×√3÷2=3/2. So I chose D.

To explain geometry and its three views, it is necessary to cultivate spatial imagination. Construct geometry in the brain through three views, and then transform the known conditions into each other to achieve the purpose of solving problems.