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The title of the chapter "Three Inequalities" in Senior Two Mathematics.
The problem was solved graphically:

Let x = a+b y = a-b.

x+Y = 2a & gt; =0

x-Y = 2b & gt; =0

0 = & ltx = a+b & lt; =2

-2 = & lt; y = a-b & lt; =2

The shadow area drawn by the above four inequalities is a triangle:

s= 1/2X4X2=4