Does it look like Teacher Lian?

From the attached middle school to the final finals, all the class teachers except the top ten kept their grades secret. For years, the name of this security measure was easy to find.

But, after all, I took the exam last year. What kind of problems should I report to you out of humanitarianism?

[Note] I didn't know that you had an orange paper in Kangda, University of Connecticut, and your paper (attached middle school to normal school, 36, 37, 5 is too simple, focusing on the following knowledge (attached middle school to Alexandria)).

The math problems in the attached middle school are not very difficult. Thinking and method of looking at the equation. Last year, I tested three engineering problems. So, should you pay attention to your thoughts? Engineering problems, travel problems. A good solution to list equation. )

Part of number theory is basically not tested, so you should look at the key points of application problems, not the problems of number theory.

English names are super simple. It is basically equivalent to the textbook of the fifth grade of primary school.

. The comprehensive use of language Last year, we took an examination of four famous buildings' poems and beautiful women, and the description of "the moon is closed and the flowers are ashamed" said that this question was taken in 06 rounds.

6。 Last year, his father's junior high school teacher was the most annoying person, so please prepare some fresh materials, even from a better angle (some dad wrote an article in my blog, you can go and have a look).

Finally, I wish you success in the exam. Is the topic in the middle school attached to the teacher too difficult, let alone difficult?

So, relax, now this is a good test.

The copy of the test paper given to you depends on the difficulty of the exam. This title is very good, basically nothing.

First, fill in the blanks:

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3。 A two-digit number, 10 bit exchange, gets two digits less than the original 27, and this condition is satisfied by * * * _ _ of two digits.

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5。 Is there a total area of blank parts? _ _ _ _ _ every _ _ _ _.

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6。 A and B are in the same river, with a distance of 2 10 km. If two ships are on the same line, and then meet in two hours, the same line, 14 hour, catches up with B, the speed of the ship is _ _ _ _ _.

7。 1 1- 17 seven digits should be filled with ○ digits, and each row of three digits is equal.

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8。 A, B and C have an average weight of 60 kg, and the average weight is more than 3 kg than propionic acid and 3 kg than C, so the weight of B is _ _ _ _ _ _.

9。 There is a number, divided by 3, the remainder is 2, the remainder divided by 4 is 1, and the remainder divided by 12 is _ _ _.

10。 Seven coins are heads (face value) Turn it over several times, face a row, turn 6 or 7 coins in the opposite direction, and face up _ _ _ _ _ (fill in yes or no).

Secondly, to answer this question:

1。 70% alcohol solution, 300g 500g alcohol solution, 50% alcohol solution, what is the alcohol concentration in the mixed solution?

2。 Total triangular number-number graph?

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3。 A four-digit number, the first number is equal to 0 digits, the second number represents/kloc-0 digits, the third number represents the digits in Figure 2, and the four numbers are equal to the digits in Number. Find four digits.

Xiao Sheng's Early Series Simulation Test Paper (1) Answers

First, fill in the blanks:

1。 ( 1)

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3。 (6)

The original two digits are 10a+b, and then the new two digits are 10b+ after the switch position 10a. The difference between them (10A+b)- (Figure 10b +)=(A, B)= 27.

4。 (99)

5。 (half)

It is correct to replace the area of the left semicircle with the right half of the semicircle.

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6。 (60 km/h)

The two ships met for two hours. The sum of the two ships' speeds is 210 ÷ 2 =105 (km/h); Two ships on the same route, 14 hours to catch up with B and A? -B speed? = 210 ÷14 =15 (km/) and the poor problem: (105+15) ÷ 2 = 60 (km/h).

B 60- 15 = 45 (km/h).

7. 1 1 + 12 + 13 + 14 + 15 + 16 + 17 = 98。 If the number represented by the central circle is the sum of three lines, because each number appears once, it is only twice as much as 1-3, so it should be a multiple of 3 at 98 +2 A, = 1 1, 12. ..., 17 to 98 +2 A, a =1,14,17,98+2 a is a multiple of 3 ...

( 1)= 1 1, 98+= 120 120÷3 = 40.

(2) When 1 = 14, 98+= 126, 126÷3 = 42.

(3) When A = 17, 98+= 132, 132÷3 = 44.

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The solution is shown in the above figure.

8。 (6 1)

The average weight of A, B and C is more than 3 kg, and the ratio of 3×2 = 6 (kg) is 2? What's up, Gaby? The weight of 3 kg is known, but B is 6-3 = 3 kg more than propionic acid. And the weight difference between propionyl and propionyl is generally equal to the average weight of 3, so the weight of propoxy is 60-(3x2) ÷ 3 = 58 (kg), and B = 58 +3 = 6 1 (kg).

9。 (5)

The smallest integer that meets the conditions is 5, and then it is accumulated to the least common multiple of 3 and 4, all integers. If the conditions are met, 5, 17, 29, 4 1, ... are multiples of 12, so they have the same remainder divided by 12.

10。 (no)

The negative effect of 7 coins is the biggest, accounting for 7 odd coins of the total number of people, but each time it is opened with 6 or 7 coins, so no matter how many times it is turned over, the sum of the times is several or even, so the title requirements cannot be obtained.

Secondly, to answer this question:

1。 (62.5%)

The weight of mixed alcohol solution is 500 +300 = 800 (g), the content of pure alcohol after mixing is 500× 70%+300× 50% = 350150 = 500 (g), and the concentration of the mixture is 500 ÷ 800 = 0.

2。 (44)

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(1) First, observe the inner rectangle, which is represented by the smallest triangles 8 and 4 in the figure 1 and consists of two small triangles; There are four small triangles composed of triangles, and the innermost rectangle has 16 triangles.

(2) The rectangle in Figure 2 extends inside, and the extended part is a triangle added by a dotted line. The smallest triangle has eight 4: triangle and two small triangles; It consists of four small triangles, the triangle is 4× 4; The triangle is made up of eight small triangles, so the new 28. (1), (2), called the total triangle: 16 +28 = 44 ().

3。 (12 10 and 2020)

The analyzed numbers and positions start with the four-digit number 0, and the MSB is not zero, so at least one number is 0. If the three numbers 0, the first number and the last four digits are all non-zero, then the number above four digits. Therefore, the number of zeros can be more than two.

(1) has only one 0, so the first digit is 1, and 2 can't be 0, but it can't be 1 to 2, which is necessary, so there is a 1, and then it is always 2, and the last digit of 1 is 0; The second number cannot be greater than 2.

(2) There are exactly two zeros, only two, and the third place cannot be zero, two or four zeros. Now it is in the third place, because the second and fourth places are 0, so it can't be 1 and Figure 3, but it can be three or more places and can only be 2.

4。 (0.239)

? 0.2392 ...& lt Original