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Solve the problem of candy mathematics
Suppose the first box originally contained candy X, then the second box originally contained candy176-X. ..

Take out 16 pieces from the second box and put them in the first box. At this time, the number of blocks in the first box is 3 1 more than that in the second box, and x+1 6 = m (160-x)+31,that is, x =160-/kl. When 1+m=5, the minimum value of x is 13 1.