From the former, beauty is not 1, and learning is not 1 (because if it is, it does not conform to "different Chinese characters represent different numbers").
Because beauty at least =2, wonderful at most =4, otherwise multiplication will become 4 digits; And learn at most =7, otherwise the addition will not be established.
Then there is a simple discussion in different situations.
If beauty =2, Miao must be 4 (even number, not 0, not repeated with other Chinese characters), learning =7, number =9, and see if the equation: 2*497=994 2+497=499 meets the conditions.
If beauty =3, beauty may be 1, 2, and it is impossible after discussion respectively (if beauty = 1, then learning =7, number = 4,3 *147 = 441is satisfied, and addition is not satisfied; If wonderful =2, then learning =4.
If beauty =4, then beauty =8, learning =2, there is no suitable number.
If beauty is greater than 5, then Miao must be = 1, then beauty can only be 7 or 9.
If beauty =7 and magic = 1, then learning =3, and there is no suitable number.
If beauty =9 and magic = 1, there is no suitable study.
To sum up, wonderful mathematics =2497.
Of course, my approach is rigorous, and I denied all the possibilities behind after giving an answer. If it is a fill-in-the-blank question in primary school, you can stop if you do it right. This is the rule of the exam. . .