So 1 10 △ 3 is10-1+12 =11,
②x△7 is x+3=2003,
So x=2000.
B. first a≠0, then a+b=0, so b
/a
=- 1, b= 1, a=- 1, so a+3b = 2. So the answer is: 2.
C.
A can't be 0, so D can't be 0, so A and D can be 1, 2, 3, 4, 5, 6, 7, 8, 9 and * *, and B and C can be 0, 1, 2, 3, 4, 5, 6, 7.
So the four-digit symmetry number * * * has 9× 10=90 (pieces).
It's really abnormal. . .