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A math problem in grade one,,,,, Math Emperor, please come in,,, The answer should be original, and the steps should be absolutely detailed.
Suppose that the average speed from Beijing to Tianjin during this trial operation is one kilometer per hour.

Then the average speed from Tianjin to Beijing is +40 km/h.

(A+40)x0.5 is the distance from Tianjin to Beijing (speed x time = distance).

AX(30+6)/60 is the distance from Beijing to Tianjin (estimated half an hour, 6 minutes more).

The distance from Beijing to Tianjin is equal to the distance from Tianjin to Beijing (needless to say)

So (A+40)x0.5=AX(30+6)/60.

Just solve the equation. A= 200 kilometers per hour.

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