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Primary school students' mathematical thinking training, the fifth grade, the second volume, the first lecture, the answer to the fourth question
Let s △ PCD = X, s △ PBC = Y, s △ PAC = Z.

S△PAB+S△PCD=S△PAD+S△PBC=S parallelogram /2

Namely: 5+x=2+y y-x=3.

S △ ACD = S △ PCD+S △ Pad+S △ PAC = S △ PAB+S △ PBC-S △ PAC = S △ ABC = S parallelogram /2

Namely: x+2+z = 5+y-z.

2z=3+y-x=3+3=6

z=3

The area of △PAC is 3, please use it.