The solution of the first inequality is x < a- 1.

Multiply both sides of the second inequality by 6 to get 3x+27+6≥2x+2-6, and the solution is x≥-37.

If the inequality group has solutions, the intersection of the solutions of two inequalities {x | < a- 1} and {x|≥-37} is not an empty set, so we get a- 1 >-37, a >-36.