Because of one? B & gt=0, then the boundary of the condition should be y=-2x+6? And y=-x/2+3, the forbidden zone is below the image, because x? Y & gt=0, so the restricted area of the topic becomes X axis, Y axis, y=-2x+6? The area enclosed by y=-x/2+3 is the orange area in the figure.

Let 2x+3y=c, that is, y=-2x/3+c/3, and make y=-2x/3 parallel lines, then the maximum intercept when parallel lines intersect the orange area is found.

Obviously, when y=-2x/3+c/3 crosses y=-2x+6? When it is at the focus (2,2) of y=-x/2+3, the intercept is the largest. If (2,2) is brought into y=-2x/3+c/3, we can get c= 10.

Matching images should be easier to understand.