Answer:
Solution: NF⊥AD, vertical foot f, connection DD ′, nd ′,
∵ Fold the square paper ABCD in half, so that the D point falls on the D' point on the AB side, and the crease is MN.
∴dd′⊥mn,
∠∠A =∠DEM = 90,∠ADD′=∠EDM,
∴△dad′∽△dem,
∴∠dd′a=∠dme,