∴OA=3,OB= 1

∫△AOB?△COD

Then OC=OA=3 and OD=OB= 1.

∴C coordinate (0,3), AD=OA+OD=3+ 1=4.

2.△COD is a right triangle, and OM=CM.

Then m is the midpoint of the CD, m coordinate (1/2,5/2).

Substitute c and m coordinates into:

c=3

(1/2) squared+1/2b+3=5/2.

b=-3/2

Then y = the square of x -(3/2)x+3.