(1) connects P'C, because triangle ABC is an equilateral triangle.

So the angle ABC = 60 degrees.

Because pbp' = 60 degrees (rotated by 60 degrees), the angle ABP= = the angle P'BC.

In triangle ABP and triangle CBP', AB = CB, angle ABP = angle CBP' BP = BP'.

So triangle ABP is equal to triangle CBP.

So CP' = AP = 5

In the triangle PBP', the angle PBP' = 60 degrees, Pb = P' b? ,

So the triangle PBP is an equilateral triangle. So PP' = 3.

Triangle CPP' is a right triangle with the inverse theorem of Pythagorean theorem. So the angle CPP' = 90 degrees. 2) We know from (1) that the angle BPP' = 60 degrees,

Angle CPP' = 90 degrees,

So CPB angle = 150 degrees.