Examination analysis: (1) According to the meaning of the question, we can first calculate the number of students in the whole school of 20 13.

(2)① Let the per capita reading amount in 20 12 years be X, and that in 20 13 years be (x+ 1). We can establish an equation and draw a conclusion according to the quantitative relationship between the total reading volume.

② From the conclusion of ①, we can find out the per capita reading of the reading club in 20 12 years, the per capita reading of the reading club in 20 14 years, and the per capita reading of the whole school. We can establish an equation and find out the solution from the relationship between the reading volume of the reading club in 20 14 years and the reading volume of the whole school.

Problem analysis: Solution: (1) According to the meaning of the question, the number of students in the whole school in 20 1000 × (1+10%) =100.

∴ The number of students is 201100+100 =1200.

(2)① Let the per capita reading in 20 12 years be X, then the per capita reading in 20 13 years is (x+ 1).

1100 (x+1) =1000x+1700, solution: x = 6.

Answer: In 20 12 years, the average reading volume of the whole school was 6.

② According to the meaning of the question, the average reading amount of the reading club in 20 12 years is 2.5×6= 15, and that in 2015 years is15 (1+a) 2,20/kloc-0.

According to the meaning of the question, that is,

The solution is a 1 =- 1 (truncation), a2 = 0.5.

A: The value of A is 0.5.