There are two possibilities: \r\n① Sodium hydroxide is liquid, and then electrolyzed water. \ r \ nMethod: 2h++2e-→ H2 ↑ r \ nanode: 4oh-→ 2h2o+O2 ↑+4e-\ r \ nGeneral formula: 2h2o = 2h2o+O2 ↑ (. N Anode: 4OH -→ 2H2O+O2 ↑+4e-\ r \ nGeneral formula: 4NaOH = 4Na+2h2o+O2 ↑ (the reaction condition is electrifying).