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Math problems: duck egg 4 points 1, egg 3 points 1, bird egg 11. 1 yuan has run out of money. How can I buy 100 eggs?
1 yuan can buy 25 duck eggs, 33 eggs, 1000 bird eggs.

Therefore, the number of duck eggs and eggs cannot exceed 33, so there are at least 67 bird eggs. In this way, the possibility of egg number is 70, 80, 90.

So this problem is simplified.

Suppose there are 70 eggs, plus 30 eggs and duck eggs, leaving 0.93 yuan.

Let x eggs and y duck eggs be 3x+4y=93 x+y=30, and x=27 y=3.

So, the answer is 3 duck eggs, 27 eggs and 70 bird eggs.

Suppose there are 80 bird eggs, plus 20 eggs and 20 duck eggs, leaving 0.92 yuan.

Suppose there are x eggs and y duck eggs, then 3x+4y=92 x+y=20 gives y = 32 and x =- 12. Obviously, this solution is ineffective.

Similarly, 90 eggs is impossible, because it is impossible to spend 0.9438+0 yuan money to buy 10 eggs and duck eggs.

The final answer: 3 duck eggs, 27 eggs and 70 bird eggs.