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This is a mathematical problem related to balance and weight. What is the answer and how to work it out? Ask the great god for advice. I'm stupid. I'd better have a process.
The normal balance is 1: 1, assuming that the balance of unequal arms is 1:n, n≠ 1.
The former rice is 5n, and the latter rice is 5/n .. 5n+5/n = 5 (n+1/n) ≥ 5× 2 =10. And n≠ 1, so the sum is >: 10kg.