The most important thing is the learning process!
? We are confused, we grope, we explore, and we have real gains!
Don't think the following analysis is long and difficult, some of them are for the sake of being more comprehensive.
Just a few pictures.
? There are two solutions to the second problem, among which there are similarities. Pay attention to the difference and choose.
One that you can easily understand.
? I also burn the midnight oil after school to find time to do it. Painting is ok, but I type.
It's too slow to keep you waiting!
Tip: As shown in the figure,
As shown in the figure,
(3) there is such a point q.
The idea is that according to the property that the diagonal of a parallelogram is equally divided and the opposite sides are parallel and equal,
In the condition, a, o, p and q are four points, where a and o are fixed points, then the line segment AO has
There are two possibilities: first, AO is diagonal; Then AO is the side of the parallelogram.
When AO is diagonal, as shown in figure PQ is another diagonal, P( 1,-1) and Q(-2,-1) can be easily obtained;
When AO is an edge, there are two situations:
(1)Q(-2,-1) remains unchanged, and P moves to the left of A, so it is easy to get P(-3,-3);
(2) When p (1,-1) remains unchanged, Q moves to the right of A, and it is easy to get Q(0,-3);
To sum up, the coordinate groups of all eligible points P and Q are:
P( 1，- 1)，Q(-2，- 1)；
P(-3，-3)，Q(-2，- 1)；
P( 1，- 1)，Q(0，-3).