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The seventh grade math equation problem.
One-third (x-6) = one-half to one-fifth (x+2)

Solution: Divide by the denominator (both sides are multiplied by 30) and get: 10(x-6)= 15-6(x+2).

Without the brackets, we get:10x-60 =15-6x-12.

Move the item and get:10x+6x =15-12+60.

Combining similar projects, we get 16x=63.

Both sides of the equation are divided by 16 at the same time, and 63 of x = 16 is obtained.

I hope it will help you (* _ _ *) ~!