Suppose the distance between the two stops is X, and when they meet for the first time, car A will go (x/2)- 12.

Take bus B (x/2)+12;

When we meet for the second time, car A turns left again (x/2)+ 12+20=(x/2)+32.

Car B turns left again (x/2)-12+x-20 = (3x/2)-32;

As long as the speed of the two cars is unchanged and the driving time is unchanged, the distance ratio of the two cars will remain unchanged;

Therefore [(x/2)-12]: [(x/2)+12] = [(x/2)+32]: [(3x/2)-32] = > x =1/kl.

Attendant: The distance between the two stations is112km.