The first question, using the area invariance method, lists the square area = (x+y) 2 and the rectangular area =Y(2Y+X)/2, and the two areas are equal, and calculates X=3Y/4, that is, X/Y=3/4.

Question 2:1:op = oc-PC = 2/2-1/6 *18/5 = 2/5, AQ =1/9 *18/5 = 2/.

2 small problem: AQ=OP, that is, PC-OA=OP, that is, t/6- 1=t/9, calculate t= 18, and if the lengths of the other two sides are both equal to 2, it is a diamond.

3 Small problem: AB=BP can form 1 diamond, at this time CP= root number 3; AP=BP can form another diamond, CP =1; AP=PA can form a third diamond, CP=2- root number 3.