This question is not difficult. It investigates the solution of the intersection of quadratic functions and the judgment of right triangle. Think about it carefully and you should be able to do it. Answer/exercise/math /798 135, you'd better look at the analysis first, not the answer, and see what the idea of this question is and how to analyze it. I hope you can adopt it.

The other intersection point of parabola Y = x2-2mx (m > 0) and X axis is A, and P( 1, -m) is a parabola where PM⊥x axis intersects with point B, and the symmetry point of point B about the parabola axis is C. 。

(2) let m > 1 connect CA, and if △ACP is a right triangle, find the value of m;

(3) Is there a point E on the coordinate axis, so that △PEC is an isosceles right triangle with P as the right vertex? If it exists, find the coordinates of point e;