The steps are as follows:
(1) 3% and 8% and 5% respectively, both of which are larger values, and the smaller values are cut off to get 2% and 3% respectively;
The obtained values are 3% and 8% saline and 5% saline concentration difference, respectively.
(2) then crossing the two differences to take the ratio;
3% brine quality: 8% brine quality = 3% difference in ①: 2% difference in ① = 3: 2.
(3) Calculate the dosage of 3% and 8% brine in proportion.
The quality of brine is 1000×3÷(3+2)= 600g.
The mass of brine with 8% sum is 1000×2÷(3+2)=400 (g).
I wonder if I can understand the step-by-step answer for your reference.
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