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The problem of income from the application of equation in the sixth grade of science mathematics
Solution: If the purchase price of B is regarded as 1 and the purchase price of A is 88%, then the profit of B is 20%.

A's profit is 88% × 20% = 17.6%.

So the cost of B is 24 ÷ (20%-17.6%) =1000 yuan.

So the cost of A is 1000× 88% = 880 yuan.

So the price of A is 880× (1+20%) = 1056 yuan.

Solution: The monthly interest rate is the monthly interest rate, which is calculated in months, so the interest:

2500× 5.1%×12 =153 (yuan)

Principal and interest:

2500+ 153=2653 (yuan)

A year later, Mr. Wang Can received interest 153 yuan, and the principal interest was 2653 yuan.

Solution: Original profit 1.2* 1800*0.3.

85% of the original profit is1.2 *1800 * 0.3 * 0.85.

Assuming that the price of surplus notebooks is X, the profit of surplus notebooks should be (X- 1.2)* 1800*0.2.

The profit before price reduction is 1.2* 1800*0.3*0.8.

Then the equation1.2 *1800 * 0.3 * 0.85 =1.2 *1800 * 0.3 * 0.8+(x-1.2) */

The original price is1.2 * (1+0.3) =1.56.

So the remaining notebook price is 1.29/ 1.56, which is about 0.827, or 82.7%.

Solution: If melons are all the same size:

Let the price on the first day be A, then we can get 2a+3*0.8a+5*0.8*0.8a=38, and get a=5.

So if they are all bought on the third day, it is 10*0.8*0.8*5=32 yuan.

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