1. Substitute b and c into the straight line y=kx+b to get the result.
k=-3/2,b=3/2
So the resolution function y of BC is -3/2x+3/2.
2. Because the slope of the straight line OC =-3.
So the slope of the ED line =-3.
Y=-3x+b into point e.
b=-6
So the analytical formula of the ED line is y=-3x-6.
Because BC intersects with Ed,
So -3x-6=-3/2x+3/2.
X=-5,y=9。
3. Because the abscissa of BC line is f (1, 0).
S quadrilateral CDEO=S△DEF-S△OCF
= 1/2x3x 9- 1/2x 1x 3
= 12