1. Substitute b and c into the straight line y=kx+b to get the result.

k=-3/2，b=3/2

So the resolution function y of BC is -3/2x+3/2.

2. Because the slope of the straight line OC =-3.

So the slope of the ED line =-3.

Y=-3x+b into point e.

b=-6

So the analytical formula of the ED line is y=-3x-6.

Because BC intersects with Ed,

So -3x-6=-3/2x+3/2.

X=-5，y=9。

3. Because the abscissa of BC line is f (1, 0).

S quadrilateral CDEO=S△DEF-S△OCF

= 1/2x3x 9- 1/2x 1x 3

= 12