3*3*3=27

2*2*6*27-6*6*6=432 cm？

Answer: You can get 27 small cubes. The surface area increased by 432 cm?

Question 14: Let the height of this iron block be Xcm.

10* 10* 10= 1/3*(20/2)^2*3. 14*x

Solution: X≈ 10

Question 15: The forward distance is π×/kloc-0 /×15 =15π = 47.1m.

The compression area is 47./kloc-0 /×1.2 = 56.52m2..

Question 16: .......................