A junior high school math password problem

This problem is directly transformed into an algebraic problem:

x 1+2 x2 = 9+26m；

3 x2 = 16+26n；

X3+2X4 = 23+26p；

3 x4 = 12+26q；

Constraints:

0≤X 1，X2，X3，X4≤26；

M, n, p and q are integers and 0 ≤ m, n, p and q ≤ 2 (this conclusion can be drawn according to the characteristics of the above equation).

By using the method of making up numbers and trial and error, we can get the following results:

X 1=7

X2= 14

X3= 15

X4=4

So the word is hope.