Meaning from the question: when x takes 6/6 π as the maximum value, substitute x into the above formula to get A=6.
2: Y=6sin(2x+3 π) after left shift, and y=g(x)=6sin(4x+3 π) after shortening.
When x takes 5π of 24, y= 65438+ 0 of minus 2.
When x takes 1 of 24, Y = 1.
Answer: negative two thirds 1, 1.
18, 1: Because AE is perpendicular to BD, we can get that AD is perpendicular to BD by lifting, and we can get the first question.
2. Coordinate system: CF is the z axis, CB is the x axis, and CD is the y axis. Let CB= 1.
Find the normal vector n 1=( 1, 1, 1) of triangles FDB and DBC, and N2 = (0,0, 1).
Press cos
19, 1: p (a) = 3/4 times 1+4 times 1 times 2/3 times 1+4 times 1.
2: (I draw vertically)
X P
0 36 1
1 12 part 1
2 9 1
Two thirds 1
4 9 1
5/3 1
Part 02 of ex = 65438+4 1
I'm so tired. Good luck in the exam!