The sixth grade of primary school, the first volume of mathematics training, 57 pages, answer by yourself.
The sixth grade elementary school mathematics exercise book, volume one, page 27, urgently seeking an answer! Urgent! Urgent! The answer to 13 is 1. The following correspond, but the mapping from p to m is () A.P={ positive integer}, M={- 1, 1}, F: X→ (- 1) XB. P = {Y2=|x| Answer: D Analysis: Because any non-zero real number in P has two opposite numbers corresponding to it in M.2. In the following groups of functions, () a.f (x) = 1, g (x) = x0b.f (x) = x2, which one of g (x) represents the same function? Only two functions with the same domain and corresponding rules can be the same function. The domain of A.g(x) is x ≠ 0, that of f (x) is R.B.g(x) is x≠2, and that of f(x) is x ≠ 2. F( 1)=, f (x 2) = f (x) f (2), then f(5) is equal to () a.0b.1c. D.5 answer: c analysis: special case method: f(x)=x meets the meaning of the question. Therefore, f(5)=. Direct method: x =-1f (1) = f (-1) f (2) f (1) =-f (1) f (2) = .4. Let the quadratic function f(x)=ax2 bx c(a≠0), if f (x1) = f (x2) (x1≠ x2), then f(x 1 x2) is equal to g(x)= a. 0,f(2)& lt; F( 1), get a.