Answer:
Solution:
Such as 1 square, as shown in the figure.
Point A is AM⊥BC, vertical foot is M, and point N is GH.
∴∠AMC=90,
∵ quadrilateral EFGH is a square,
∴GH∥BC,GH=GF,GF⊥BC,
∴∠AGH=∠B,∠ANH=∠AMC=90。
∠∠GAH =∠BAC,
∴△AGH∽△ABC.
∴AN:AM=GH:BC,
The area of ABC is 12, and BC is 6.
∴ s △ ABC =1/2 (BC× am) =1/2× 6× am =12, and the solution is AM = 4.
Let GH=x, BC=6, AM=4,
GF = NM = GH,
∴AN=AM-NM=AM-GH=4-x,
∴x/6=(4-x)/4,x=/ 12/5,
Similarly, when n=2, x= 12/7,
Therefore, for n squares, x= 12/(2n+3),
So choose: D.