{//This is for A and B. You don't have to look at it, you know.

First of all, the area of the whole rectangle is 24(DC x EC), so the area of triangle ABE is: AE x BE/2 = 24/4 = 6; ; That is AE x be =12; Combining OA x BE = 6, we can see OA/AE =1/2; So OA = CD/3 = 2；; Easy to know be = 3；;

}

Next, because the area of ABCDO is 24 * 3/4 = 18, that is, the area of AODP =18/2 = 9; Let P(x, y);

First, if the point P is on the straight line AB, the equation of the straight line AB must be satisfied, and the equation 1 is obtained.

Secondly, make a line perpendicular to OE through point P and intersect OE at m, which can be obtained by the area formula:

Right trapezoid ODPM- triangle AMP = ODPA = 9；; ; -Equation 2 is obtained.

Simultaneous, one yuan twice, can get its solution.