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Just like ab in mathematics.
Solution: The area of (1)∑△ECF is equal to the area of quadrilateral EABF.

∴S△ECF:S△ACB= 1:2

You: EF AB

∴△ECF∽△ACB

s△ecf:s△acb=(ce/ca)^2= 1/2

And AC = 4.

∴CE=2√2

(2) let the length of CE be x.

∫△ECF∽△ACB

∴CE/CA=CF/CB

∴CF=3/4x

According to the fact that the perimeter of △ECF is equal to the perimeter of quadrilateral EABF, it can be concluded that

x+CE+3/4X=(4-X)+5+(3-3/4X)+CE

The solution is all-weather

The length of ce is 24/7.