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Ten most difficult math problems in history
As shown in the figure, A, B, C, D and E are arranged clockwise, representing one to five primary schools in turn, and X 1, X2, X3, X4 and X5 computers are assigned to adjacent schools in turn according to the meaning of the questions.

7+x 1-x2 = 1 1+x2-x3 = 3+x3-x4 = 14+x4-X5 = 15+X5-x = 10

X2 = x 1-3, x3 = x 1-2, x4 = x 1-9, X5 = x 1-5 are obtained.

Y = │ x1│+│ x2 │+│ x3 │+│ x4 │+│ X5 │ From the meaning of the question, the work efficiency of Party A is 1/20, that of Party B is130, and that of both parties is/kloc-0.

Because it is required that "the fewer days the two teams work together, the better", Party A should be made to work faster./kloc-If it is too late within 0/6 days, Party A should cooperate with Party B.. Only in this way can the two teams work together as little as possible.

Let the cooperation time be x days, then Party A will do it alone for (16-x) days.

1/20 *( 16-x)+7/ 100 * x = 1。 According to the meaning of the question, 1/4 represents the cooperation workload of Party A and Party B, and 1/5 represents the cooperation of Party B and Party C..

(1/4+1/5) × 2 = 9/10 means that Party A worked for 2 hours, Party B worked for 4 hours and Party C worked for 2 hours.

According to "After Party A and Party C work together for 2 hours, Party B needs to work for 6 hours", we can know that the workload of Party A working for 2 hours, Party B working for 6 hours and Party C working for 2 hours is 1.

So1-9/10 =110 means that B works for 6-4 = 2 hours.

110 ÷ 2 =1/20 indicates the work efficiency of Party B. ..

1 ÷ 1/20 = 20 hours means that it takes 20 hours for Party B to complete it alone. According to the meaning of the question,

1/A+ 1/B+ 1/A+ 1/B+…+ 1/A = 1。

1/B+ 1/A+ 1/B+ 1/A+…+ 1/B+ 1/A×0.5 = 1。

(1/ A represents the working efficiency of A, 1/ B represents the working efficiency of B, and the final outcome must be as shown in the above figure, otherwise the second method will not be 0.5 days longer than the first one).

1/a =1/b+1/a× 0.5 (because the previous workload is equal).

Get 1/ A = 1/B× 2.

Because1/b =117.

So 1/ A = 2/ 17, and A = 17 ÷ 2 = 8.5 days.

The answer is 300.

120 ÷ (4/5 ÷ 2) = 300

You can think of it this way: 1/2 for the first time and 1/2 for the second time are all done at once. Then after the second time, the apprentice completed 4/5, and it can be inferred that half of the 4/5 completed for the first time is 2/5, which is exactly 120.

A:B It takes 20 hours to finish it alone.

x= 10

A: The shortest cooperation period between Party A and Party B is 10 day.

= │ x1│+│ x1-3 │+│ x1-9 │+│ x1-5 │ minimum value.

According to the geometric meaning of absolute value, when x 1=3, y has a minimum value of 12,1/20+116 = 9/80, indicating the working efficiency of both parties.

9/80× 5 = 45/80 indicates the water quantity after 5 hours.

1-45/80 = 35/80 indicates the required water intake.

35/80 ÷ (9/80-110) = 35 means it takes 35 hours to fill it.

A: It will take 35 hours to fill the pool after 5 hours.

At this time, x2 = 0, x3 = 1, x4 =-6, X5 =-2,

That is, three computers turn from one small to two small, 1 from three small to four small, six from five small to four small, and two from one small to five small, so the number of computers that turn at least is 12.