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Under what circumstances should the equal area method be used in mathematical problems?
1.

1.2 *1.3 =1.56, so the area will be 56% larger.

2. Solution: Let a * * * be the X lock, and according to the meaning of the question, we get 2/3(8/3x)+8/5x=380. Note: Two thirds is three thirds.

The solution is x=320.

3. Divide the hexagon into six regular triangles along the center of the hexagon. Compared with the original triangle, the side length ratio of any triangle is 2: 3 and the area ratio is 4: 9, so the area of triangle divided by hexagon is 9/( 12 * 4), and the area of hexagon is 9/( 12 * 4).

4. The topic seems to be wrong. The minimum degree can be zero. At 3: 59/900, the hour hand coincides with the minute hand, and the degree is zero. Hope to adopt