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The fourth grade mathematics second volume expands the problem.
If the first beam has 2x branches, then three branches are (2x-3) and all other beams are (2x-3), then the second beam has (2x-5), the third beam has (4x-6) and the fourth beam has (x- 1.5). * * * has 55 branches, so 2x+(2x-5)+(4x-6)+(x-1.5) = 55, that is, 9x = 67.5 and x = 7.5.

So the first bundle has 15, the second bundle has 10, the third bundle has 24, and the fourth bundle has 6.